求一个 nginx 地址重写规则

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当匹配到地址 http://xxx/sites/app/avatar/0F0993200F910338F0EE638EFDFA1779 要求请求 http://xxx/sites/app/index.php?m=user&c=index&a=avatar&user_id=0F0993200F910338F0EE638EFDFA1779

下面的写法好像不行

	location / {
	   rewrite ^sites/app/avatar/(.*)$  /sites/app/index.php?m=user&c=index&a=avatar&user_id=$1 last;
       try_files $uri $uri/ =404;
	}

5 replies • 2018-07-19 16:48:54 +08:00

yangg

Jul 19, 2018

rewrite ^/sites....$

少了个 /

mafeifan

Jul 19, 2018

location / {
rewrite ^sites/app/avatar/(.*)$ /sites/app/index.php?m=user&c=index&a=avatar&user_id=$1 last;
try_files $uri $uri/ =404;
}

# pass PHP scripts to FastCGI server
location ~ \.php$ {
include snippets/fastcgi-php.conf;
fastcgi_pass unix:/var/run/php/php7.0-fpm.sock;
}

还是报 404，求助啊

mafeifan

Jul 19, 2018

rewrite ^/sites/app/avatar/(.*)$ /sites/app/index.php?m=user&c=index&a=avatar&user_id=$1 last;

wu67

Jul 19, 2018

\/sites\/app\/avatar\/(.*)$

这样?

imdong

Jul 19, 2018

不需要 location 字段也可以噻

server {
listen 80;
root "/web";

# 重写规则
rewrite ^/sites/app/avatar/(.*)$ /sites/app/index.php?m=user&c=index&a=avatar&user_id=$1 last;

location ~ \.php(.*)$ {
fastcgi_pass 127.0.0.1:9000;
...
}
}