8F，这算是倍数吗

7F

@Riscly 不想再引入 redis 进入订单

@IMCA1024 这会导致插入订单

@qiayue 我也考虑过这样，innodb delete 会锁表吗

@zunceng 如果有几十个容器，怎么搞呢

屁用没有，谁会用？

@inroading 不会吧不会吧，还有人不懂？

之前写的,可以参考下

```
package xaes

import (
"bytes"
"crypto/aes"
"crypto/cipher"
"crypto/rand"
"crypto/sha256"
"encoding/base64"
"github.com/pkg/errors"
)

type Aes struct {
key []byte
}

func NewAes(key string) (*Aes) {
if key == "" {
panic("aes key empty")
}
sum := sha256.Sum256([]byte(key))
return &Aes{
key:sum[:],
}
}

func (a *Aes) Encrypt(encodeBytes []byte) (val string, err error) {
block, err := aes.NewCipher(a.key)
if err != nil {
return
}
blockSize := block.BlockSize()
encodeBytes = a.pkCS5Padding(encodeBytes, blockSize)

iv := make([]byte, blockSize)
_,err = rand.Read(iv)
if err != nil {
return
}

blockMode := cipher.NewCBCEncrypter(block, iv)
crypted := make([]byte, len(encodeBytes))
blockMode.CryptBlocks(crypted, encodeBytes)

iv = append(iv,crypted...)
val = base64.StdEncoding.EncodeToString(iv)
return
}


func (a *Aes) pkCS5Padding(ciphertext []byte, blockSize int) []byte {
padding := blockSize - len(ciphertext)%blockSize
padtext := bytes.Repeat([]byte{byte(padding)}, padding)
return append(ciphertext, padtext...)
}

func (a *Aes) Decrypt(decodeStr string) (origData []byte,err error) {
decodeBytes, err := base64.StdEncoding.DecodeString(decodeStr)
if err != nil {
return
}
block, err := aes.NewCipher(a.key)
if err != nil {
return nil, err
}
if len(decodeBytes) < block.BlockSize() {
err = errors.New("decodeBytes 长度不足")
return
}
iv := decodeBytes[:block.BlockSize()]
decodeBytes = decodeBytes[block.BlockSize():]

blockMode := cipher.NewCBCDecrypter(block, iv)
origData = make([]byte, len(decodeBytes))
blockMode.CryptBlocks(origData, decodeBytes)
origData = a.pkCS5UnPadding(origData)
return
}

func (a *Aes) pkCS5UnPadding(origData []byte) []byte {
length := len(origData)
unpadding := int(origData[length-1])
return origData[:(length - unpadding)]
}
```

好用的标准是什么？

我要中奖

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